Classification Of Elements And Periodicity In Properties Question 154
Question: A compound AB whose electro negativity difference is 1.9. Atomic radius of A and B are 4 and $ 2,\overset{o}{\mathop{A}}, $ . The distance between A & B means $ {d_{A-B}} $ is
Options:
A) $ 6.72,\overset{o}{\mathop{A}}, $
B) $ 5.82,\overset{o}{\mathop{A}}, $
C) $ 6.9,\overset{o}{\mathop{A}}, $
D) $ 7.5,\overset{o}{\mathop{A}}, $
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Answer:
Correct Answer: B
Solution:
[b] Given $ r_{A}=4\overset{o}{\mathop{A}},,r_{B}=2\overset{o}{\mathop{A}},,\Delta x=1.9 $
By the formula $ {d_{A-B}}=r_{A}+r_{B}-0.09,(\Delta x) $ $ =4+2-.09\times 1.9=6-0.171=5.82\overset{o}{\mathop{A}}, $
BETA
