Classification Of Elements And Periodicity In Properties Question 169
How many elements would be in the second period of the Periodic Table if the spin quantum number $ m_{s} $ could have the value $ -\frac{1}{2},+\frac{1}{2} $ -
Options:
8
10
12
18
Show Answer
Answer:
Correct Answer: C
Solution:
[c] For second period $ n=2 $ hence I am $ m_{s} $ 0 0 $ +\frac{1}{2},0,-\frac{1}{2} $ 1 - 1 $ +\frac{1}{2},0,-\frac{1}{2} $ 0 1 $ +\frac{1}{2},0,-\frac{1}{2} $ +1 $ +\frac{1}{2},0,-\frac{1}{2} $ Hence, total number of elements = 12 (= total values of spin quantum number)
BETA
