Classification Of Elements And Periodicity In Properties Question 170
Question: Which of the following order is CORRECT for the property mentioned in brackets:
Options:
A)$ {{S}^{2-}}>C{{l}^{-}}> $ $ {{K}^{+}}>C{{a}^{2+}} $ (Ionisation energy)
B)$ C<N\gt F<O $ ( $ 2^{nd} $ Ionisation energy)
C)$ B>AI>Ga> $ $ In>TI $ (Electronegativity)
D)$ N{{a}^{+}}>L{{i}^{+}}>M{{g}^{2+}}> $ $ B{{e}^{2+}}>A{{l}^{3+}} $ (Ionic Radius)
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Answer:
Correct Answer: B
Solution:
[b] [a] Correct order $ \to C{{a}^{2+}}>{{K}^{+}}>C{{l}^{-}}>{{S}^{2-}} $ (lonisation energy) For Isoelectronic species $ (IE\propto Z_{eff}) $ [b] Correct order $ \to C<N<F<O $
$ (2^{nd}IE) $ Second electron removal from oxygen requires more energy as it acquires stable $ 2s^{2}2p^{3} $ configuration after removal of one electron. [c] Correct order $ \to B>TI>In>Ga>Al $ (Electronegativity) In general EN increases in boron family from top to bottom due to increase in $ Z_{eff} $ on valence shell while Boron has highest E.N. due to its very small size. [d] Correct order $ \to N{{a}^{+}}>L{{i}^{+}}>M{{g}^{2+}} $
$ >A{{l}^{3+}}>B{{e}^{2+}} $ (Ionic radius) Ionic radius depends on $ z_{eff} $ and number of shells.
BETA
