Co Ordination Compounds Question 156
Question: The number of geometrical isomers for octahedral $ {{[ Co{{( NH_3 )}_2}Cl_4 ]}^{-}} $ , square planar $ AuCl_2Br_2^{-} $ and $ {{[Co(NO_2){{(NH_3)}_5}]}^{2+}} $ are
Options:
A) 2, 2, 2
B) 2, 2, no isomerism
C) 3, 2, 2
D) 2, 3, no isomerism
Show Answer
Answer:
Correct Answer: B
Solution:
The number of geometrical isomers $ {{[Co{{(NH_3)}_2}{{(Cl)}_4}]}^{-}}-2 $
$ AuCl_2Br_2-2 $
$ {{[ Co( NO_2 ){{( NH_3 )}_5} ]}^{2+}} $ - No isomerism
BETA
