Co Ordination Compounds Question 198
Mixture $ X=0.02,mol $ of substance
[Co{{(NH_3)}_5}SO_4],Br $ and 0.02 mol of $ [Co{{(NH_3)}_5}Br]SO_4 $ was prepared in 2 litre of solution 1 litre of mixture X + excess $ AgNO_3\to Y $ . 1 litre of mixture X + excess $ BaCl_2\to Z $ Number of moles of Y and Z are [IIT JEE 2003]
Options:
A) 0.01, 0.01
B) 0.02, 0.01
C) 0.01, 0.02
D) 0.02, 0.02
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{0.02,mole}{\mathop{[Co,{{(NH_3)}_5}SO_4],Br}},+AgNO_3\to $
$ \underset{0.02,\text{mole }(y)}{\mathop{[Co,{{(NH_3)}_5}.,SO_4],NO_3}},+AgBr $
$ \underset{0.02,mole}{\mathop{[Co,{{(NH_3)}_5}Br_2]SO_4}},+BaCl_2\to $
$ \underset{0.02,mole,(z)}{\mathop{[Co,{{(NH_3)}_5}Br],Cl_2}},+BaSO_4 $ On using one lit.
Solution, we will get 0.01 mole of Y and 0.01 mole of Z.
BETA
