Co Ordination Compounds Question 259
Question: Considering $ H_2O $ as a weak field ligand, the number of unpaired electrons in $ {{[Mn{{(H_2O)}_6}]}^{2+}} $ will be (At. No. of Mn = 25) asas a ajkk
[CBSE PMT 2004]
Options:
A) Two
B) Four
C) Three
D) Five
Show Answer
Answer:
Correct Answer: D
Solution:
$ Mn^{25}\xrightarrow{{}}3d^{5}+4s^{2} $
$ M{n^{2+}}\xrightarrow{{}}3d^{5} $ In presence of weak ligand field, there will be no pairing of electrons.
So it will form a high spin complex.
i.e.
the number of unpaired electrons = 5.
BETA
