A) 2
B) 6
C) 5
D) 4
Correct Answer: B
$ [Co,{{(en)}_2}Br_2],Cl_2 $
$ C.N.,\text{of },Co= $ 2 × number of bidentate ligand +1×number of monodentate ligand =2× 2 + 1× 2 = 6.
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