Co Ordination Compounds Question 39

Question: $ AgCl $ is soluble in $ NH_4OH $ solution. The solubility is due to formation of

Options:

A) $ AgOH $

B) $ Ag_2O $

C) $ {{[Ag{{(NH_3)}_2}]}^{+}} $

D) $ NH_4Cl $

Show Answer

Answer:

Correct Answer: C

Solution:

$ AgCl $ form soluble complex with $ NH_4OH $ which is $ {{[Ag{{(NH_3)}_2}]}^{+}} $ .



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