Co Ordination Compounds Question 43
Question: The total number of possible isomers of the complex compound $ [Cu^{II}{{(NH_3)}_4}][Pt^{II}Cl_4] $ is
Options:
3
6
5
4
Show Answer
Answer:
Correct Answer: D
Solution:
For $ [Cu^{II}{{(NH_3)}_4}[Pt^{IV}Cl_4] $ four isomers are possible which are $ [Cu{{(NH_3)}_4}[PtCl_4] $ , $ [CuCl_4],[Pt{{( NH_3 )}_4}][PtCl_3( NH_3 )][Cu{{( NH_3 )}_3}Cl] $ and $ [ Pt{{( NH_3 )}_3}Cl ][ Cu( NH_3 )Cl_3 ] $
BETA
