Co Ordination Compounds Question 55
Question: Coordination number of Cr is six. A complex with $ C_2O_4^{2-} $ , en and superoxide $ O_2^{-} $ will be in the ratio to make complex $ {{[Cr{{(C_2O_4)} _{x}},{{(en)} _{y}}{{(O_2)} _{z}}]}^{-}} $
Options:
A) x-1 y-1 z-1
B) x-1 y-1 z-2
C) x-1 y-2 z-2
D) x-2 y-1 z-1
Show Answer
Answer:
Correct Answer: D
Solution:
$ C{r^{3+}},C_2O_4^{2-},{{(en)}^{0}},O_2 $
$ C_2O_4^{2-} $ and $ {{( en )}^{0}} $ are bidentate ligands.
CN of $ Cr^{3+} $=6,
Oxalate and en are bidentate ligands.
BETA
