Co Ordination Compounds Question 60
Question: The pair in which both species have same magnetic moment (spin only value) is
Options:
A) $ {{[Cr{{(H_2O)}_6}]}^{2+}},{{[CoCl_4]}^{2-}} $
B) $ {{[Cr{{(H_2O)}_6}]}^{2+}},{{[Fe{{(H_2O)}_6}]}^{2+}} $
C) $ {{[Mn{{(H_2O)}_6}]}^{2+}},{{[Cr{{(H_2O)}_6}]}^{2+}} $
D) $ {{[CoCl_4]}^{2-}},{{[Fe{{(H_2O)}_6}]}^{2+}} $
Show Answer
Answer:
Correct Answer: B
Solution:
Same magnetic moment = Same number of unpaired electrons.
$ \mu =\sqrt{n(n+2)} $ where n = number of unpaired electrons $ C{o^{2+}}=3d^{7},3 $ unpaired electrons; $ C{r^{2+}}=3d^{4},4 $ unpaired electrons; $ M{n^{2+}}=3d^{5},5 $ unpaired electrons; $ F{e^{2+}}=3d^{6},4 $ unpaired electrons.
BETA
