[MP PET 2004]
2
4
5
0
Correct Answer: A
$ Ni\to 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{8}4s^{2} $
$ N{{i}^{2+}}\to 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{8} $
$ 3d^{8}=10-2=8 $ unpaired electron.
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