D And F Block Elements Question 436
The correct order of magnetic moments (spin only values in B.M.) among the given species is
[AIEEE 2004]
Options:
A) $ {{[Fe{{(CN)}_6}]}^{4-}}>{{[MnCl_4]}^{2-}}>{{[CoCl_4]}^{2-}} $
B) $ {{[MnCl_4]}^{2-}}>{{[Fe{{(CN)}_6}]}^{4-}}>{{[CoCl_4]}^{2-}} $
C) $ {{[MnCl_4]}^{2-}}>{{[CoCl_4]}^{2-}}>{{[Fe{{(CN)}_6}]}^{4-}} $
D) $ {{[Fe{{(CN)}_6}]}^{4-}}>{{[CoCl_4]}^{2-}}>{{[MnCl_4]}^{2-}} $ (Atomic nos. $ Mn=25,,Fe=26,,Co=27 $ )
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Answer:
Correct Answer: C
Solution:
Magnetic moment $ =\sqrt{n(n+2)} $ Where, n = number of unpaired electron i.e., greater the number of unpaired electron greater will be the paramagnetic character.
BETA
