D And F Block Elements Question 438
Question: What is the oxidation number of iron in the compound $
[Fe{{(H_2O)}_5}(NO)]SO_4 $ [Pb. CET 2001]
Options:
A) $ +2 $
B) $ +3 $
C) $ \pm 1 $
D) $ \pm 4 $
Show Answer
Answer:
Correct Answer: A
Solution:
Applying the oxidation number rule in $ [Fe{{(H_2O)}_5}(NO)]SO_4 $ ( $ \because $ $ H_2O $ and NO are neutral)
$ [x+(0)\times 5+0]+(-2)=0 $ $ x+0+0-2=0 $
Þ $ x=+2 $ Hence, oxidation number of Fe is +2.
BETA
