D And F Block Elements Question 468
Question: $ F_2 $ is the formed by reacting $ K_2MnF_6 $ with
[AIIMS 2005]
Options:
A) $ SbF_5 $
B) $ MnF_3 $
C) $ KSbF_6 $
D) $ MnF_4 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ K_2MnF_6~+2SbF_5\to 2KSbF_6+MnF_3+\frac{1}{2}F_2 $
In this reaction, the stronger Lewis acid $ SbF_5 $ displaces the weaker one, $ MnF_4 $ from its salt.
$ MnF_4 $ is unstable and readily decomposes to give $ MnF_3 $ and fluorine.
BETA
