D And F Block Elements Question 67
Question: General configuration of outermost and penultimate shell is $ (n-1),s^{2},(n-1)p^{6}(n-1)d^{x}ns^{2}. $ If n = 4 and x = 5 then no. of proton in the nucleus will be
[MP PET 2003]
Options:
A) > 25
B) < 24
C) 25
D) 30
Show Answer
Answer:
Correct Answer: C
Solution:
Given n = 4 x = 5 So $ \underset{3s^{2}}{\mathop{(4-1)s^{2}}},\underset{3p^{6}}{\mathop{(4-1)p^{6}}},\underset{3d^{5}}{\mathop{(4-1)d^{5}}},\underset{4s^{2}}{\mathop{4s^{2}}}, $ Total electron = 2 + 6 + 5 + 2 = 15 Electron in 1 + 2 orbit = 2 + 8 = 10 Total electron = 10 + 15 = 25 No. of electron = No. of proton So total proton = 25
BETA
