Equilibrium Question 14

Question: The solubility product of a sparingly soluble salt $ AB $ at room temperature is $ 1.21\times {10^{-6}} $ . Its molar solubility is [CPMT 1987; MP PET 2001]

Options:

A) $ 1.21\times {10^{-6}} $

B) $ 1.21\times {10^{-3}} $

C) $ 1.1\times {10^{-4}} $

D) $ 1.1\times {10^{-3}} $

Show Answer

Answer:

Correct Answer: D

Solution:

AB is a binary electrolyte. $ S=\sqrt{K _{sp}}=\sqrt{1.21\times {10^{-6}}}=1.1\times {10^{-3}}M $



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