Equilibrium Question 33
$ K _{sp} $ for sodium chloride is $ 36mol^{2}/L^{2}. $ The solubility of sodium chloride is [BHU 1981]
Options:
A) $ \frac{1}{36} $
B) $ \frac{1}{6} $
6
D) 3600
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Answer:
Correct Answer: C
Solution:
NaCl → $ \begin{matrix} N{a^{+}}, & + & ,C{l^{-}} \\ S, & {} & ,S \\ \end{matrix} $
$ K _{sp}=S^{2} $ , $ S=\sqrt{K _{sp}}=\sqrt{3.6\times10^{-5}}=6\times10^{-3} $ .
BETA
