Equilibrium Question 37
In the reaction: $ H_2S $ ⇄ $ 2{H^{+}}+{S^{2-}} $ , when $ NH_4OH $ is added, then [KCET (Med.) 1999; AFMC 2000]
Options:
A) $ {S^{2-}} $ is precipitate
B) No action takes place
C) Concentration of $ {S^{2-}} $ decreases
D) Concentration of $ {S^{2-}} $ increases
Show Answer
Answer:
Correct Answer: D
Solution:
In IVth group the $ {S^{2-}} $ concentration increases when added the $ NH_4OH $ because
$ NH_4OH $ ⇌ $ NH_4^{+}+O{H^{-}} $
$ H_2S $ ⇌ $ 2{H^{+}}+{S^{2-}} $
$ OH^{-}+{H^{+}} $ ⇌ $ H_2O $ . So that $ {S^{2-}} $ is increased.
BETA
