Equilibrium Question 40
Question: Solubility product of a salt AB is $ 1\times {10^{-8}} $ in a solution in which concentration of A is $ {10^{-3}}M $ . The salt will precipitate when the concentration of B becomes more than [MP PET 1990; KCET 2003]
Options:
A) $ {10^{-4}}M $
B) $ {10^{-7}}M $
C) $ {10^{-6}}M $
D) $ {10^{-5}}M $
Show Answer
Answer:
Correct Answer: D
Solution:
$ [B]=\frac{K _{sp}AB}{[A]}=\frac{1\times {10^{-8}}}{{10^{-3}}}=1\times {10^{-5}}M $ Where ionic product > $ K _{sp},,ppt $ formed
$ \therefore $ 8 should be more then $ {10^{-5}}M $ .
BETA
