Equilibrium Question 42
Question: At equilibrium, if to a saturated solution of $ NaCl,,HCl $ is passed, $ NaCl $ gets precipitated because [RPMT 1999]
Options:
A) $ HCl $ is a strong acid
B) Solubility of $ NaCl $ decreases
C) Ionic product of $ NaCl $ becomes greater than its $ K _{sp} $
D) $ HCl $ is a weak acid
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Answer:
Correct Answer: C
Solution:
$ NaC{l_{(s)}} $ ⇌ $ Na_{(aq)}^{+}+Cl_{(aq)}^{-} $
$ HCl $ ⇌ $ {H^{+}}+C{l^{-}} $ . The increase in $ [C{l^{-}}] $ brings in an increase in $ [N{a^{+}}] $
$ [C{l^{-}}] $ which will lead for backward reaction because $ K _{sp}(NaCl)=[N{a^{+}}][C{l^{-}}] $ means Ionic product $ \ge K _{sp} $
BETA
