Equilibrium Question 444
Question: $ CH_3COO{H_{(l)}}+C_2H_5O{H_{(l)}} $ ⇌ $ CH_3COOC_2{H_{5,(l)}}+H_2{O_{(l)}} $ In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. $ H_2SO_4 $ . On equilibrium being attained [CPMT 1985; MP PET 1992]
Options:
A) 1 mole of ethyl acetate is formed
B) 2 mole of ethyl acetate are formed
C) 1/2 moles of ethyl acetate is formed
D) 2/3 moles of ethyl acetate is formed
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Answer:
Correct Answer: D
Solution:
In presence of little $ H_2SO_4 $ (as catalyst) about 2/3 mole of each of $ CH_3COOH $ and $ C_2H_5OH $ react to form 2/3 mole of the product at equilibrium.
BETA
