Equilibrium Question 499
Question: For reaction, $ 2A(g) $ ⇌ $ 3C(g)+D(s) $ , the value of $ K_{c} $ will be equal to [Pb. CET 2003]
Options:
A) $ K_{p}(RT) $
B) $ K_{p}/RT $
C) $ =K_{p} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ 2A(g) \leftrightharpoons$ $ 3C(g)+D(s) $
For this reaction, $ \Delta n_{g}=3-2=1 $
$ \therefore K_{p}=K_{c}{{[RT]}^{1}} $ or $ \frac{K_{p}}{K_{c}}=RT $ or $ K_{c}=\frac{K_{p}}{RT} $
BETA
