Equilibrium Question 51
Question: Why pure $ NaCl $ is precipitated when $ HCl $ gas is passed in a saturated solution of $ NaCl $ [NCERT 1977; MP PMT 1987; CPMT 1974, 78, 81]
Options:
A) Impurities dissolve in $ HCl $
B) The value of $ [Na^{+}] $ and $ [Cl^{-}] $ becomes smaller than $ K _{sp} $ of $ NaCl $
C) The value of $ [Na^{+}] $ and $ [Cl^{-}] $ becomes greater than $ K _{sp} $ of $ NaCl $
D) $ HCl $ dissolves in the water
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Answer:
Correct Answer: C
Solution:
$ NaC{l_{(s)}} $ ⇌ $ N{a^{+}} _{(aq)}+C{l^{-}} _{(aq)} $
$ HCl $ ⇌ $ {H^{+}}+C{l^{-}} $ The increase in $ [C{l^{-}}] $ brings in an increase in $ [H^{+}] $
$ [C{l^{-}}] $ which will lead to backward reaction because $ K _{sp},NaCl=[N{a^{+}}][C{l^{-}}] $ .
BETA
