Equilibrium Question 514
Question: 4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction $ A+B $ ⇌ $ C+D $ , 2 moles of C and D are formed. The equilibrium constant for the reaction will be [CPMT 1992]
Options:
A) $ \frac{1}{4} $
B) $ \frac{1}{2} $
C) 1
D) 4
Show Answer
Answer:
Correct Answer: C
Solution:
$ A+B $ ⇌ $ C+D $ Initial conc. 4, 4 0 0 After T time conc. (4-2) (4-2) 2 2 Equilibrium constant = $ \frac{[C][D]}{[A][B]}=\frac{2\times 2}{2\times 2}=1 $
BETA
