Equilibrium Question 544
Question: A reaction is $ A+B\to C+D $ . Initially we start with equal concentration of $ A $ and $ B $ . At equilibrium we find the moles of $ C $ is two times of $ A $ . What is the equilibrium constant of the reaction [BHU 1998; KCET 2000]
Options:
4
2
C) $\frac{1}{4}$
D) $ 1/2 $
Show Answer
Answer:
Correct Answer: A
Solution:
A+ B ⇌ C+ D at equilibrium a a 2a 2a $ K=\frac{2a\times 2a}{a\times a}=4 $
BETA
