Equilibrium Question 564
The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. K equilibrium is [KCET 2002]
Options:
2.5
2.0
0.5
1.5
Show Answer
Answer:
Correct Answer: B
Solution:
The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. $ K_{equilibrium} $ is 2 because the reaction is reversible. So $ K=\frac{K_1}{K_2}=\frac{2}{1}=2 $ .
BETA
