Equilibrium Question 565
Question: The equilibrium constant (Kc) for the reaction $ HA+B $ ⇌ $ B{H^{+}}+{A^{-}} $ is 100. If the rate constant for the forward reaction is 105, then rate constant for the backward reaction is [CBSE PMT 2002]
Options:
A) $ 10^{7} $
B) $ 10^{3} $
C) $ {10^{-3}} $
D) $ {10^{-5}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ K_{c}=\frac{K_{f}}{K_{b}}\therefore ,K_{b}=\frac{K_{f}}{K_{c}}=\frac{10^{5}}{100}=10^{3} $
BETA
