A) $ CH_3COONa $
B) $ NH_4Cl $
C) $ NaCl $
D) $ CH_3COONH_4 $
Correct Answer: B
$ NH_4Cl+H_2O $ ⇌ $ \underset{Weak,base}{\mathop{NH_4OH}},+\underset{Strong,acid}{\mathop{HCl}}, $ . So it is acidic in nature.
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