Equilibrium Question 580
Question: What is the equilibrium expression for the reaction $ {P_{4(s)}}+5{O_{2(g)}} $ ⇌ $ P_4{O_{10(s)}} $ [AIEEE 2004]
Options:
A) $ K_{c}={{[O_2]}^{5}} $
B) $ K_{c}=[P_4O_{10}]/5[P_4][O_2] $
C) $ K_{c}=[P_4O_{10}]/[P_4]{{[O_2]}^{5}} $
D) $ K_{c}=1/{{[O_2]}^{5}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ P_4(s)+5O_2(g) $ ⇌ $ P_4O_{10}(s) $
$ K_{c}=\frac{[P_4O_{10}(s)]}{[P_4(s)]{{[O_2(g)]}^{5}}} $ We know that concentration of a solid component is always taken as unity $ K_{c}=\frac{1}{{{[O_2]}^{5}}} $
BETA
