Equilibrium Question 623
Question: Solubility product of a sulphide MS is $ 3\times {10^{-25}} $ and that of another sulphide NS is $ 4\times {10^{-40}} $ . In ammoniacal solution [NCERT 1981]
Options:
A) Only NSP gets precipitated
B) Only MS can get precipitated
C) No sulphide precipitates
D) Both sulphides precipitate out
Show Answer
Answer:
Correct Answer: D
Solution:
The concentration of $ {S^{2-}} $ ions in group II is lowered by maintaining acidic medium in the presence of $ NH_4Cl $ . The ionization of $ H_2S $ is supressed due to common ion effect. So the ionic product is less than solubility product.
BETA
