Equilibrium Question 645
Question: In the equilibrium $ CH_3COOH+HF $ ⇄ $ CH_3COOH_2^{+}+{F^{-}} $ [BHU 1987]
Options:
A) $ {F^{-}} $ is the conjugate acid of $ CH_3COOH $
B) $ {F^{-}} $ is the conjugate base of $ HF $
C) $ CH_3COOH $ is the conjugate acid of $ CH_3COOH_2^{+} $
D) $ CH_3COOH_2^{+} $ is the conjugate base of $ CH_3COOH $
Show Answer
Answer:
Correct Answer: B
Solution:
$ CH_3COOH+HF $ ⇌ $ CH_3COOH_2^{+}+{F^{-}} $ . $ HF $ gives $ {H^{+}} $ to the $ CH_3COOH $ . So it is a conjugate base of HF.
BETA
