Equilibrium Question 673
The standard Gibbs energy change at 300 K for the reaction $ 2A\to B+C $ is 2494.2 J. At a given time, the composition of the reaction mixture is [A]= $ \frac{1}{2} $, [B]=2, and [C]= $ \frac{1}{2} $ . [R=8.314 J/Kmol, e=2.718]
Options:
A) forward direction because $ Q<K_{C} $
B) reverse direction because $ Q<K_{C} $
C) forward direction because $ Q>K_{C} $
D) reverse direction because $ Q<K_{\text{eq}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta G=\Delta G^{o}+RT $ In Q $ =249.2+8.314\times 300 $ In 4 =Positive $ \Delta G=RT $ In $ \frac{K}{Q} $ Since, $ \Delta G $ is positive so Q<K, so reaction shifts in reverse direction.
BETA
