Equilibrium Question 701
Question: What is the $ pH $ value of $ \frac{N}{1000},KOH $ solution [CPMT 1975; MNR 1986, 91; Pb. CET 2004]
Options:
A) $ {10^{-11}} $
3
2
11
Show Answer
Answer:
Correct Answer: D
Solution:
$ {10^{-2}}N $ KOH will give $ [OH^{-}}]={10^{-2}} $ M $ pOH=2 $
$ \because ,pH+pOH=14 $ , $ pH=14-2=12 $
BETA
