Equilibrium Question 732
Question: For the reaction: $ 2BaO_2(s)\rightarrow 2BaO(s)+O_2(g); $
$ \Delta H=+ve. $ In equilibrium condition, pressure of $ O_2 $ is dependent on
Options:
A) mass of $ BaO_2 $
B) mass of $ BaO $
C) temperature of equilibrium
D) mass of $ BaO_2 $ and $ BaO $ both
Show Answer
Answer:
Correct Answer: C
Solution:
For the reaction $ 2BaO_2(s)\rightarrow 2BaO(s)+O_2(g);\Delta H=+ve $ At equilibrium $ K_{p}={P_{O_2 }} $ Hence, the value of equilibrium constant depends only upon partial pressure of $ O_2 $ . Further on increasing temperature formation of $ O_2 $ increases as this is an endothermic reaction. Hence, pressure of $ O_2 $ is dependent on temperature.
BETA
