Equilibrium Question 743
Question: Consider the expression $ \Delta G=- RT \ln K_{p}+RT \ln Q_{p} $ and indicate the correct statement at equilibrium
Options:
A) $ \Delta G=0,Q _{p}\gt K _{p} $ the equilibrium reaction will shift from left to right
B) $ \Delta G=0,Q _{p}=K _{p} $ the equilibrium reaction will shift from left to right
C) $ \Delta G=\infty ,Q _{p}\lt K _{p} $ the equilibrium reaction will shift from right to left
D) $ \Delta G\lt 0,Q _{p}\gt K _{p} $ the equilibrium reaction will shift from right to left where $ Q _{p} $ and $ K _{p} $ term refer to reaction quotient and equilibrium constant at constant pressure respectively.
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Answer:
Correct Answer: B
Solution:
Van’t Hoff reaction isotherm is $ \Delta G=\Delta G{}^\circ +RT $ In Qp When the reaction is in a state of equilibrium $ \Delta G=0 $ Then $ \Delta {G^{{}^\circ }}=-RT ln Q_{p}=-RT $ ln $ K_{p} $
BETA
