Equilibrium Question 747
Question: The following equilibrium is established when hydrogen chloride is dissolved in acetic acid. $ HCl+CH_3COOH\rightarrow C{l^{-}}+CH_3COOH_2^{+} $ The set that characterises the conjugate acid- base pairs is
Options:
A) $ (HCl,CH_3COOH)and(CH_3COOH_2^{+},C{l^{-}}) $
B) $ (HCl,CH_3COOH_2^{+})and(CH_3COOH,C{l^{-}}) $
C) $ (CH_3COOH_2^{+},HCl)and(C{l^{-}},CH_3COOH) $
D) $ (HCl,C{l^{-}})and(CH_3COOH_2^{+},CH_3COOH) $
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Answer:
Correct Answer: D
Solution:
$ HCl $ is stronger acid than $ CH_3COOH $ and $ C{l^{-}} $ is a stronger base than $ CH_3COOH_2^{+} $ and is the conjugate base of $ HCl $ . $ \underset{acid_1}{\mathop{HCl}},+CH_3C\underset{base_2}{\mathop{OOH}}\rightarrow \underset{base_1}{\mathop{C{l^{-}}}},+\underset{acid_2}{\mathop{CH_3COOH_2^{+}}}, $
BETA
