Equilibrium Question 771
Question: What is the pH of a $ {10^{-4}}M,O{H^{-}} $ solution at 330K, if $ K_{w} $ at 330K is $ {10^{-13.6}} $ -
Options:
A) 4
B) 9.0
C) 10
D) 9.6
Show Answer
Answer:
Correct Answer: D
Solution:
Given at 330 K $ K_{w}={10^{-13.6}} $ i.e. $ pK_{w}=pH+pOH $
$ \therefore pOH=-log[ O{H^{-}} ] $
$ 13.6=pH+pOH $
$ pOH=-log{10^{-4}} $
$ pOH=4 $
$ \therefore pH=13.6-4=9.6 $
BETA
