Equilibrium Question 780
Question: The solubility product of $ Ag_2CrO_4 $ is $ 32\times {10^{-12}} $ . What is the concentration of $ CrO_4^{2-} $ ions in that solution (in g $ {L^{-1}} $ )
Options:
A) $ 2\times {10^{-4}} $
B) $ 8\times {10^{-4}} $
C) $ 8\times {10^{-8}} $
D) $ 16\times {10^{-4}} $
Show Answer
Answer:
Correct Answer: A
Solution:
For ternary electrolyte; solubility $ ={{( \frac{K _{sp}}{4} )}^{\frac{1}{3}}}={{( \frac{32\times {10^{-12}}}{4} )}^{\frac{1}{3}}}=2\times {10^{-4}} $
BETA
