Equilibrium Question 8
The solubility product of $ 1\times {10^{-5}} $ is $ 1.44\times {10^{-10}} $ at $ 100^{o}C $ . The solubility of silver chloride in boiling water may be [MP PMT 1994; Bihar MEE 1998]
Options:
A) $ 0.72\times {10^{-4}}M $
B) $ 1.20\times {10^{-2}}M $
C) $ 80^{o}C, $
D) $ 0.5 M HCOOH, $
Show Answer
Answer:
Correct Answer: B
Solution:
AgCl ⇌ $ [A{g^{+}}][C{l^{-}}] $ ; $ K _{sp}=S\times S $ ; $ K _{sp}=S^{2} $
$ S=\sqrt{K _{sp}} $
$ =\sqrt{1.44\times {10^{-4}}} $
$ =1.20\times {10^{-2}} $ M.
BETA
