Equilibrium Question 835
15 moles of $ H_2 $ and 5.2 moles of $ I_2 $ are mixed and allowed to attain equilibrium at $ 500^{o}C $ . At equilibrium, the concentration of $ HI $ is found to be 10 moles. The equilibrium constant for the formation of $ HI $ is
Options:
50
15
100
25
Show Answer
Answer:
Correct Answer: A
Solution:
$ H_2 $ + $ I_2 $
$ \rightarrow $ $2HI(g)$
15 5.2 0 (155) (5.25) 10 $ K_{C}=\frac{{{[HI]}^{2}}}{[H_2][I_2]}=\frac{10\times 10}{10\times 0.2}=50 $
BETA
