Equilibrium Question 836
The reaction, $ 2SO_{2(g)} + O_{2(g)} $
$ \rightarrow $ $2SO_{3(g)}$ is carried out in a 1 $ dm^{3} $ vessel and $ 2\ dm^{3} $ vessel separately. The ratio of the reaction velocities will be
Options:
A) $ 1:8 $
B) $ 1:4 $
C) $ 4:1 $
D) $ 8:1 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ 2SO_2(g)+O_2(g) $
$ \rightarrow $ $2SO_2(g)$
For $ 1dm^{3} $
$ R=k{{[SO_2]}^{2}}[O_2] $
$ R=K\ {{[ \frac{1}{T} ]}^{2}}[ 1 ]=1 $
For $ 2dm^{3} $
$ R=K\ {{[ \frac{1}{2} ]}^{2}}[ \frac{1}{2} ]=\frac{1}{8} $
So, the ratio is 8 : 1
BETA
