Equilibrium Question 839
Question: The vapour density of completely dissociated $ NH_4Cl $ would be
Options:
A) Slightly less than half that of $ NH_4Cl $
B) Half that of $ NH_4Cl $
C) Double that of $ NH_4^+ $
D) Determined by the amount of solid $ NH_4Cl $ in the experiment
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{Normal\ molecular\ weight}{experimental\ molecular\ weight} $ = 1 + a $ NH_4Cl $
$ \rightarrow $ $NH_3+HCl $
$ \because \alpha =1 $ \Experimental Molecular wt = $ \frac{nom\text{.mol}\text{.wt}\text{.}}{2} $
BETA
