Equilibrium Question 880
Question: Match List I with List II and select the correct answer using the code given below the lists
| List I | List II |
|---|---|
| [A] pH of 0.1 M HA $ (pK_{a}=5) $ and 0.01 M NaA | (p) 4 |
| [B] pH of 0.1 M BOH $ (pK_{b}=6) $ and 0.1 M BCI | (q) 7 |
| [C] pH of 0.1 M salt of HA $ (pK_{a}=5) $ and BOH $ (pK_{b}=7) $ | (r) 6 |
| [D] pH of 500 litre of 0.2 M $ HNO_3 $ and 500 litre 0.2 M NaOH | (s) 8 |
Codes:
Options:
A) A $ \to $ p, B $ \to $ s, C $ \to $ r, D $ \to $ q
B) A $ \to $ s, B $ \to $ p, C $ \to $ r, D $ \to $ q
C) A $ \to $ p, B $ \to $ r, C $ \to $ s, D $ \to $ q
D) A $ \to $ p, B $ \to $ s, C $ \to $ q, D $ \to $ r
Show Answer
Answer:
Correct Answer: A
Solution:
$ pH=pK_{a}+{\log_{10}}[ \frac{Salt}{Acid} ]= $
$ 5+{\log_{10}}[ \frac{0.1}{0.01} ]=4 $
[b] $ pOH=pK_{b}+{\log_{10}}[ \frac{0.1}{0.1} ]=6 $
$ pH=14-6=8 $
[c] $ pH=\frac{1}{2}[pK_{w}+pK_{a}-pK_{b}]= $
$ \frac{1}{2}[14+5-7]=6 $
[d] Neutral solution $ pH=7 $
BETA
