Equilibrium Question 897
Question: 10 mL, of a strong acid solution of $ pH=2.000 $ are mixed with 990 mL of another strong acid solution of $ pH=4.000 $ . The pH of the resulting solution will be:
Options:
A) 4.002
B) 4.000
C) 4.200
3.7
Show Answer
Answer:
Correct Answer: D
Solution:
$ [{\text{H}^{+}}] $ after mixing $ =\frac{{10^{-2}}\times 10+{10^{-4}}\times 990}{1000} $
$ \frac{0.1 - 0.0990}{1000}=\frac{0.0010}{1000}=1.00\times {10^{-6}} $
$ \therefore $ $pH=4-0.3=3.7 $
BETA
