A) Markowikoff’s
B) Bayer
C) Saytzeff
D) Wurtz
Correct Answer: C
$ \underset{2-Bromobutane}{\mathop{CH_3-\underset{\underset{Br}{\mathop{|}}}{\mathop{CH}}-CH_2-CH_3}}\to CH_3-CH=CH-CH_3+HBr $
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