Hydrocarbons Question 180

Question: Which of the following yield both alkane and alkene [AFMC 2004]

Options:

A) Kolbe’s reaction

B) Williamson’s synthesis

C) Wurtz reaction

D) Sandmeyer reaction

Show Answer

Answer:

Correct Answer: A

Solution:

Kolbe’s methods - Electrolysis of a concentrated aqueous solution of either sodium or potassium salts of saturated mono carboxylic acids yields higher alkanes at anode.

$ CH_3COONa $ ⇌ $ CH_3CO{O^{-}}+Na+ $

Anode : $ 2CH_3CO{O^{-}}\xrightarrow{-2{e^{-}}}CH_3-CH_3+2CO_2 $

Cathode : $ 2N{a^{+}}+2{e^{-}}\to 2Na $

$ 2Na+2H_2O\to 2NaOH+H_2 $