Hydrocarbons Question 180
Question: Which of the following yield both alkane and alkene [AFMC 2004]
Options:
A) Kolbe’s reaction
B) Williamson’s synthesis
C) Wurtz reaction
D) Sandmeyer reaction
Show Answer
Answer:
Correct Answer: A
Solution:
Kolbe’s methods - Electrolysis of a concentrated aqueous solution of either sodium or potassium salts of saturated mono carboxylic acids yields higher alkanes at anode.
$ CH_3COONa $ ⇌ $ CH_3CO{O^{-}}+Na+ $
Anode : $ 2CH_3CO{O^{-}}\xrightarrow{-2{e^{-}}}CH_3-CH_3+2CO_2 $
Cathode : $ 2N{a^{+}}+2{e^{-}}\to 2Na $
$ 2Na+2H_2O\to 2NaOH+H_2 $