Hydrocarbons Question 189
Question: Which of the following is Friedel-Craft’s reaction [MP PET 1994]
Options:
A) $ C_6H_6+FeCl_3+Cl_2\to C_6H_5Cl $
B) $ C_6H_5CHO+CH_3CHO+KOH\to C_6H_5CH=CH-CHO $
C) $ C_6H_6+CH_3COCl+AlCl_3\to \overset{O}{\mathop{\overset{||}{\mathop{C_6H_5-C-CH_3}}}} $
D) $ C_6H_5OH+CHCl_3+KOH\xrightarrow{{}}Salicylaldehyde $
Show Answer
Answer:
Correct Answer: C
Solution:
Friedel-craft’s reaction $ \underset{\text{Acetyl chloride}}{\mathop{CH_3COCl}}+\underset{Benzene}{\mathop{C_6H_6}}\xrightarrow{\text{anhydrous }AlCl_3}\underset{Acetophenone}{\mathop{CH_3COC_6H_5}}+HCl $
BETA
