Hydrocarbons Question 190
Question: Dilute aqueous $ KMnO_4 $ , at room temperature reacts with $ R-CH=CH-R $ to give [Roorkee 1992]
Options:
A) R - CHO
B) R - COOH
C) RCHOH - CHOHR
D) $ CO_2+H_2O $
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Answer:
Correct Answer: C
Solution:
$ R-CH=CH-R\underset{\text{room temp}\text{.}}{\mathop{\xrightarrow{dil\text{.aqueous }KMnO_4}}}\underset{(\text{Alcohol)}}{\mathop{R-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}-R}} $
$ R-CH=CH-R\underset{heat}{\mathop{\xrightarrow{Conc\text{.}KMnO_4}}}R-COOH+R-COOH $
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