Hydrocarbons Question 196
Question: The compound $ CH_3-\overset{CH_3}{\mathop{\overset{|}{\mathop{C=}}}}CH-CH_3 $ on reaction with $ NaIO_4 $ in the presence of $ KMnO_4 $ gives [CBSE PMT 2003]
Options:
A) $ CH_3CHO+CO_2 $
B) $ CH_3COCH_3 $
C) $ CH_3COCH_3+CH_3COOH $
D) $ CH_3COCH_3+CH_3CHO $
Show Answer
Answer:
Correct Answer: D
Solution:
$ CH_3-\overset{C{H _{3}}}{\mathop{\overset{|}{\mathop{C=CH}}}}-CH_3\underset{KMnO_4}{\mathop{\xrightarrow{NaIO_4}}}CH_3COCH_3 $
$ +CH_3CHO $
BETA
